市也在区P之0)的焦点为F,作线为L,过F且斜率为号的线门c于A,B整体两点，D为AB的中点，且DM⊥I于点M,AB的垂直分线交x轴于点N,四边形DMFN的面积为32√3，则p=遗址A.2√2B.4C.26江没柄柳D4√2对过2时二、多项选择题：本题共4小题，每小题5分，共20分.在每小题给出的四个选项中，有多项符合题目要求，全部选对的得5分，部分选对的得2分，有选错的得0分的展开式中，下列结论正确的是样A.第6项和第7项的二项式系数相等入C.常数项为84B奇数项的二项式系数和为25610.已知正实数a,b满足a+4b=2,则D.有理项有2项B.20+1624D.√a+2b≥41.已知函数f(x)=+}(o>0)在[-m引上单调，且曲线y=)关于点(-,0对称，则X+号gA.f(x)以2为周期-(x号到+到B八的图象关于直线x-罗对称5[X-2C.将(x)的图象向右移个单位长度后对应的函数为偶函数D函数y=x)+号在[0，]上有两个零点12.在长方体ABCD-A1B,CD1中，AD=2AB=2AA1=4,E是棱B,C1的中点，过点B,E,D1的面ax交棱AD于点F,点P为线段DF上一动点，则A.三棱锥P-ABE的体积为定值B.存在点P,使得DP⊥aC.直线PE与面BCC,B,所成角的正切值的最大值为2D.三棱锥P-BB,E外接球表面积的取值范围是[12π，44π]三、填空题：本题共4小题，每小题5分，共20分1及已知双鱼线G手卡1的右焦点为R点40，)，者直线气S只有}爱点，则01.b5m=数学试题2第2页（共4页）左人

当9.在同二轮·数学（四）痕气1.你拿到的试卷满分为150分，考试时间为120分钟。注意事项：2.本试卷包括“试题卷”和“答题卷”两部分。“试题卷”共4页，“答题卷”共6页。3.请务必在“答题卷”上答题，在“试题卷”上答题是无效的。人4.考试结束后，请将“试题卷”和“答题卷”一并交回。10.如目一、选择题（本大题共10小题，每小题4分，满分40分）的每小题都给出A、B、C、D四个选项，其中只有一个是符合题目要求的AD1.在以下各数中，和-2023乘积为1的是1A.-1B.0C.-2023D.20232.计算(-3x)2的结果是二、A.9x6B.9x5C.6x3D.-9x611.3.2022年12月20日，规模世界第一、装机规模全球第二大水电站一白鹤滩水电站最后一台机组正式投产发电.年均发电量能够达到624.43亿度电，可以满足约7500万人一年的生活用电，其12.中624.43亿用科学记数法表示为A.6.2443×108B.6.2443×10C.6.2443×1012D.6.2443×101013C4将一个圆锥截去一部分后得到如图所示的几何体，其俯视图是BC5.不等式x-1≥A.x≥01B.x≤0C.x≤-2D.x≥-226.将多项式。2-(26-12因式分解，正确的是A.(a+2b-1)(a-2b-1)B.(a+2b-1)(a-2b+1)C.(a+2b+1)(a+2b-1)D.(a+2b+1)(a-2b-1)7.某篮球队为了解队员冬训情况，教练从16名队员中随机选8名球员进行“跑动接球急停投篮”测试，得分如下（满分10分）：10,69,9,7,8,9,6，则以下判断正确的是A.这组数据的众数是9，说明全体队员的均成绩达到9分B.这组数据的方差是2，说明这组数据的波动很小C.这组数据的均数是8，可以估计队内其他队员的均成绩大约也是8分D.这组数据的中位数是8，说明8分以上的人数占大多数8.如图，在△ABC中，AB=AC,BC=6,BD⊥AC于点D,AD-CD=5,则cOsA的值为19A8289242C.92数学总复模拟样卷（四）第1页Ryan's fire stau

i=02,0)-(-1,成=(-1，房-,AB·n=02y=0设面PAB的一个法向量为n=(x,y,z),则,即Ap.n=0一+230令x=3,得n=（3,0,2).设PC与面PAB所成角为0，则sin0=Icos|=-5-5√217×2…12分19.(1)由题意得小明恰好套中2次的概率P=音×2×专×行+石×号×专-器.4.1,1.4428…4分(2)X的可能取值为0,1,2,3,4,5P(x=0)=x1x1-1=6×5×5=150P(X=1)=5x1x11=6x5×5=301.4.14P(X=2)=6x2×5×5=75Px=)-414×2×5×5=151448P(X=4)=6×X5=75所以X的分布列为X01234511P44881503075157515所以E(X)=12I3012分20.解：(1)为钝角三角形，证明如下：由1-sin4=1-cos2B2sin'B sinBCOSAsin2B2sinBcosB cosB'则有cosB-sinAcosB=sinBcosA,所以cosB=sin(A+B),因为A+B∈(0，π)，所以cosB=sin(A+B)>0,则B为锐角.所以coB=sim受-B=sin(A+B),所以受-B=A+B或7-B+(A+B)=m则A+2B=5或A=罗由题意知0s1≠0，所以A≠7，2所以4+2B=,所以C=m-A-B=T+B∈（受，，故△MBC为钝角三角形.…6分(2)由(1)知A+2B=5,C=7+B宣城市高三数学参考答案第2页（共4页）

You are supposed to work at staying consistent with regular exercise.Varying your routine or branching out to try newactlvitles and equlpment are some easy ways to avold getting bored.Learn to Relleve PainWhen it comes to starting or sticking to an exercise plan,pain is sometimes a source of discouragement.A massage intosore muscles can be essential to managing pain and help you maintain your commitment to a more active lifestyle.The aim ofexercise is to relax.____20__-A.But life lies in constant motlon.B.The first step is to set a goal for yourself.C.You may feel upset to have limited time.D.This will also help you measure your progress.E.I exercise in the morning to get my body functioning.F.However,it's never too late to get back on the wagon.G.Remember not to push yourself too far or past your limits.【答案】16.F17.D18.￡19.A20.6【解析】【分析】这是一篇说明文。面对生活琐事，人们往往会搁置自己原定的锻炼计划，文章就这一问题提出了几条有助于坚持锻炼变得更加健康的建议。【16题详解】"We've all been there.We eagerly begin a fitness routine only to have our motivation and enthusiasm fade when lifegets in the way.(我们都有过这样的经历：我们迫切地想要开始一项健身计划，结果却被生活琐事所累，然后我们对此的动力和热情慢慢消退)”说明我们经常制定健身计划而也通常无法坚持；下文“Here are somesuggestions that can lead you on the road to a healthier you.(以下是一些让你坚持健身之路从而变得更健康的建议)”给出建议鼓励继续，所以F项“However,it's never too late to get back on the wagon.（然而，重拾计划继续锻炼永远不晚)”符合上下文句意，起承上启下作用。故选F。【17题详解】"For example,a man initially focused on losing 30 pounds so that he could safely stop his medications.Eventually,he ended up losing45一50 pounds and was off his medications within nine months.(例如，一名男子最初的目标是减去30磅，这样他就可以安全地停止药物治疗。最后，他在九个月里减去了45到50磅，并停止了药物治疗)”举例说明了制定目标后，目标同时可以帮助人们衡量自己达成这一目标的具体进程，与D项“This will alsohelp you measure your progress.(这也将有助于衡量你的进展)”表述符合，且D项代词“This”指代上文“Startby writing a list of goal'”,承上启下。故选D。

16.解析：当203026B…4分-9分即c0s2=2则X的：学期空E(X)=0×动+1×品+2×号+3X号-骨故B=.6分0-号10分(2)由题意可得BD-BA+AD=B丽+AC棉：0岭岩得s骨BA+(BC-BA)-3 BA+BC8分当n≥2时，Sn-1=2(n-1)an-1则D-(子B函+子BC)'-6B2+冬B·C+y2a,2(n-1)aw-1两式相减，有a,一12分GBC2,即9=9-子BC1+6BC,.10分2(n-1)a-1_(n-1a2解得1BC1=12或|BC1=0(舍去)，+1故BC边的长为12.12分

半焦距为c,在RtaBFF中，BFP+BFE5,即(GaP+(}=(2c,解得S=78所以E的离心率为7故选：B【点睛】方法点睛：求双曲线离心率的三种方法：①定义法，通过已知条件列出方程组，求得a,c得值，根据离心率的定义求解离心率e;②齐次式法，由已知条件得出关于a,c的二元齐次方程，然后转化为关于e的一元二次方程求解：③特殊值法：通过取特殊值或特殊位置，求出离心率二、多选题9.已知点P在圆(x-5)2+(y-5)2=16上，点A(4,0)、B(0,2),则()A.点P到直线AB的距离小于10B.点P到直线AB的距离大于2C.当∠PBA最小时，|PB=3√2D.当∠PBA最大时，|PB=3V2【答案】ACD【分析】计算出圆心到直线AB的距离，可得出点P到直线AB的距离的取值范围，可判断AB选项的正误；分析可知，当∠PBA最大或最小时，PB与圆M相切，利用勾股定理可判断CD选项的正误.【详解】圆(x-5)2+(y-5)2=16的圆心为M(5,5),半径为4，直线AB的方程为+=1，即x+2y-4=0,圆心M到直线AB的距离为5+2×5-4_11_11V5V12+22V55>4,所以，点P到直线4B的距离的最小值为15-4<2，最大值为5+4<10，A选项正确，5B选项错误；如下图所示：

18。.(12分)已知函数f)=sm(@x+以o>0-<4<0)的周期为号，图象关于直线x-子对称3(1)求f(x)的解析式，2)在纯角三角形A8C中，角AB,C所对的过为a6c,若=受，6=2c=4,D为BC的中点，求AD的长19.(I2分)己知四棱锥P-ABCD的底面ABCD是梯形，PA⊥面ABCD,BC∥AD,AB=√2，CD=1,AD=2BC=2,PA=1.(1)求点A到面PBC的距离；(2)求面PBA与面PBC的夹角的大小ADB浙江省新阵地教育联盟2024届第一次联考高二数学试题卷第4页共6页

13.9将该组数据从小到大排列为2,4,5,6,7,8,9,10，因为8×800=6.4，所以孩组数据的80%分位数为9.21514.2,3由a+b=25,得a+b2=12,即a2+2a·b+b2=12.因为a=√6，b1=2,所/3以ab2所以wab=日8后及g得15.48π如图，设该圆锥的轴截面为△ABC,过A作AD⊥BC交BC于D,则该圆锥的外接球的球心O在AD上，OA即该圆锥外接球的半径.由题意可得AD=33,设该圆锥的外接球的半径为R,则R2=(3√3一R)2+32,解得R=2√3，故该圆锥的外接球的表面积为4πR2=48π.16.200V5由题意知∠QPM=5,∠PQM=石，所以∠QMP=乏，所以在Rt△QMP中，MP-2QP-600米，QM=5PQ=6003米.又∠QPN=，∠PQN=晋，所以∠QNP-吾在△QNp中，由正弦定理，得Q=PQ,所以QN=120×怎=4006米.在sinsim2△MNQ中，∠MQN=登-晋=子由余弦定理，得MN=√QN2+QM-2QN·QM·cos∠MQN=√(4006)+(60v3)°-2×400,6×603×9=200V15米.217.解：(1)2a十b=（-3,9),……1分因为(2a十b)∥c,所以-3入=6X9,…3分解得入=一18.…5分(2)a-3b=(-5,8),…6分因为(a-3b)Lc,所以-5X6十8入=0，…8分解得X只…10分【高一数学·参考答案第2页（共5页）】·23-523A·18.獬：(1)因为2S-√3bcc0sA=0,所以bcsin A-√3bcc0sA=0,…1分则sinA=√3cosA,所以tanA=√3.…3分又因为A∈(0，)，所以A=号…6分(2)由余弦定理，得cosA=+-a2=12bc=2,即B+2-49=bc,…8分得(b十c)2=49十3bc=169,则b十c=13,…10分故△ABC的周长为a+b十c=20.…12分19.解：(1)根据题意得(0.005十0.010+m十0.040+0.020十0.010)×10=1，…2分解得m=0.015.…3分(2)该果园这200个蜜桔的均质量约为30×0.05+40×0.10+50×0.15+60×0.40+70×0.20十80X0.10=59克/个.……6分(3)依题意可估计该果园这5万个蜜桔的总质量为5×59=295万克=2950千克.…8分若按原销售方案进行销售，则可获得的收益约为2950×25=73750元；…9分若低于55克的蜜桔以140元/百个进行销售，不低于55克的蜜桔以160元/百个进行销售，则可获得的收益约为(0.05+0.10+0.15)×500×140+(0.40+0.20+0.10)×500×160=77000元.……11分因为77000>73750，所以按新方案进行销售，该果园收益会更高。…12分20.解：(1)正三棱柱的体积V-9×1PX1-9cm.1分4正三棱台的体积V,=号×1×(9×1+气×2+√停3x1x5x2)=712cm,…3分

·数学·参考答案及解析若选择方案二，设甲可获得的奖金为Y元，则Y的所以E(X)=(1-)”+(n+1)[1-(1-)],可能取值为40,100,200,300,400，由题可知(1-)”+(n+1)[1-(1一p)"]=n,P(Y=40)=2'1即n(1-)=1,11、11整理可得p=1一P(Y=100)=2×3X=30，即b=fw=1一(6分)②当n=8时，记单次检验费用为x,PY=20)=××+号×号×（号）则方案一：检验费用为nx;(7分)方案二：记检验费为Y,则Y的分布列为Y(n+1)xP(Y=30)=2×号×C(告)×（传）=是P(1-)”1-(1-)”P(Y=400)=×号×（告）广-8则E(Y)=x(1-p)”+(n+1)x[1-(1-p)]=[n+1-n(1-)"]x,(9分)所以E)=40×号+100×0+200×号+300×E(Y)-nx=[n+1-n(1-p)"]x-nx=[1-n(1-号+40×9=10，p)]x,(11分)记g(p)=1-n(1-)”,因为E(X)0,则E(Y)0，则E>种排法所以满足条件的排法共2×2×6+12=36，故当0

参考答案(关键点：旋转前后的两个三角形全等)(AB=EF,AB=DE,CE=CB,∠DCE=∠ACB,∠A=在△ABC和△EFD中，{BC=FD,∠D,∴.∠DCE-∠ACE=∠ACB-∠ACE,即AC=ED,∠ACD=∠BCE,.·∠ACD+∠D+∠DFC=.△ABC≌△EFD(SSS).180°，∠AEF+∠A+∠AFE=180°，∠DFC=2.B∠AFE,.∠ACD=∠AEF,.∠AEF=3.C【解析】小：点A,D,C,F在同一条直线上，AD∠BCE,故②③④正确，①错误=CF,∴.AD+CD=CF+CD,即AC=DF.在△ABC3x-2y=1012.24或12【解析】由题意得或(AB=DE,x+2y=14与△DEF中，AC=DF,∴.△ABC≌△DEF3x-2y=14x=6（x=6,+2=10,解得BC=EF.或=4(y=2,.xy=24(SSS),∴.∠BCA=∠F,∠B=∠E,∠A=∠EDF,或12..BC//EF.13.(1)△ADF;2(2)证明：.△ABF≌△FCD,.∠B=∠C,4解：AB=AC,AE=弓AB,AF=同.·∠B=90°，∴.AE=AF∴.∠B+∠C=180°，∴.AB∥CD;(AE=AF,课时(3)解：AF⊥FD,AF=FD;在△ADE和△ADF中，{DE=DF,理由：.∠B=90°，∴.∠BAF+∠BFA=90°，AD=AD,暴.·△ABF≌△FCD,.△ADE≌△ADF(SSS),.DF=AF,∠DFC=∠FAB,.∠EAD=∠FAD,.AD分∠BAC.∴.∠BFA+∠DFC=90°，.在伞打开的过程中，AD始终分∠BAC.第十二章∴.∠AFD=90°，（关键点：利用全等三角形5.解：∠1=∠ACD.理由如下：的对应角相等进行等角代换)AB=BE+DE,BC=DE,∴.AF⊥FD;.AB=BE+BC,即AB=CE.(4)解：由(3)得AF⊥FD,DF=AF=8,AB=CE,六5ao2AF,DF=12×8×8=32,在△ABC和△CED中，{AC=CD,BC=ED,由折叠的性质得S AAED=S AAFD=32.(关键∴.△ABC≌△CED(SSS),∴.∠A=∠ECD点：翻折前后的图形全等)】又.∠1=∠A+∠ACE,∠ACD=∠ACE+∠ECD,14.5【解析】.正方形ABCD的面积=正方形∴.∠1=∠ACDHEFG的面积+4SAAB=12+4×6=25,.正方6.解：作图如解图所示，形ABCD的边长为5（负值已舍去）：12.2三角形全等的判定C第1课时用“SSS”判定三角形全等1.1BC=EF(答案不唯一)01.2证明：BD=CF,第6题解图.BD+CD=CF+CD,BC=DF作图依据：三条边分别相等的两个三角形全等万唯八年级QQ交流群：70330528311

P-ABC外接球的体积为32.3B.16元C.52πp.523二、多项选择题：本题共4小题，每小题5分，共20分.在每小题给出的选项中，有多项符合题目要求.全部选对的得5分，部分选对的得2分，有选错的得0分.9.下列说法正确的是A.与中位数相比，均数反映出样本数据中的更多信息，对样本中的极端值更加敏感B.数据2,3,4,5,6,7,8,9的第60百分位数为5C.已知P(A)>0,P(B)>0,P(BA)=P(B),则P(AB)=P(A)D.当样本相关系数「的绝对值越接近1时，成对样本数据的线性相关程度越强10已知点P在因0：X+y=4L.点M5,0).N0到则A.直线MN与圆O相离B.点P到直线MN的距离可能大于5C.当∠PMN最大时，|PM=√21D.满足PM⊥PN的点P有且仅有1个11.如图，已知棱长为2的正方体ABCD-ABCD,点E为AA的中点，点F为AD的中点，点G为DD的中点，则A.DE∥面CFGGB.直线CD与直线C,F所成角的余弦值为2-3C.点C与点D到面CFG的距离之比为2：1D.以D,为球心，V5为半径的球面与侧面BCCB的交线K为究第11题图12.已知抛物线C:y=4X,过焦点F的直线交抛物线于A,B两点，分别过A,B作准线(的垂线，垂足为A,B,O为坐标原点，Q(-1,0),则A.AF⊥BFB.若AF=3,则△AOF的面积为22MFC若M为抛物线C上的动点，则MQ的原值范闲为[三2D.若∠AQB=60°，则直线AB的倾斜角o的正弦值为3三、填空题：本题共4小题，每小题5分，共20分

长为x,x∈(0,7)，则圆样的高A=01-亭)6？，圆柱底面半径为兮×空-汽36x,所以圆拉表面积9-2ar+2a=2a停：)P+2a×得×6们-（行号r+7633 T&,72故当x=3 T一=4+2时S取得最大值，此时r=x=3,3x(4+2)=2,3+663BD17.【解析】(1)因为A=3P元，所以4位=3Ad,4所以Bd=B+d=B+3(B元-B=B+3BC;…4分(2)由(1)得，时.Ad-(4B+C)(BC-B=-4|g-2.BC+子1Bc,…7分因为AB=6,BC=22,∠ABC=3T,所以a时.Ad=-9-分×6x22×(-+6=3.10分18.【解析】(1)由题有4×(0.025+0.0375+0.05+a+0.0375+0.025)=1,解得=0.0750，…2分由频率分布直方图的数据，可得这100位市民走步数的均数：x=(9×0.025+13×0.0375+17×0.05+21×0.075+25×0.0375+29×0.025)×4=19.2千步；…5分(2)在[23,27)和[27,31]两组中的人数分别为100×4×0.0375=15人和100×4×0.025=10人，15所以在[23,27)分组中抽取的人数为5×10十153人，记为a1,“,4,在[27,31]分组中抽取的人数为2人，记为b1,b2,所以这5人中随机抽取2人的情况有：2={(a1,a2),(a1,a3),(a2,a3),(a1,b1),(a1,b2),(a2,b1),(a2,b2),(a3,b1),(a3,b2),(b1,b2)},共10种取法，……9分其中这2人步数都在[27,31]的情况只有{(b1,b2)},共有1种，所以这2人步数都在[27,31]的概率为P=10…12分19.【解析】(1)取AB中点0，连接P0,△PAB是正三角形，高一数学参考答案第4页（共7页）

2022-2023学年度下期高2023届三诊模拟考试英语参考答案及评分标准第一部分听力（满分30分）1~5 BCAAC6~10ABCAB11~15 ABCCC16~20 BABCC评分标准：1~20小题，每小题1.5分。第二部分第一节阅读理解（满分30分）21~23BBC24~27 CDBD28-31 AAAD32~35 BBAB评分标准：2135小题，每小题2分。第二节（满分10分）36-40 FGEBA评分标准：36~40小题，每小题2分。第三部分第一节完形填空（满分30分）41~45 BACCC46~50 ADDDA51~55 CBBBD56~60 DDCDC评分标准：41~60小题，每小题1.5分。第二节（满分15分）61.have completed 62.on63.who64.formerly65.a66.technologies 67.as68.included69.and70.to be used评分标准：61~70小题，每小题1.5分。有任何错误，包括用词错误、单词拼写错误（含大小写)或语法形式错误，均不给分。第四部分第一节短文改错（满分10分）My favourite inventor is Alexander Graham Bell.At a young age,Bell started to show muchinterest A helping deaf people communicate,which led to their invention of the microphone.inhisBeside,he also invented the telephone in 1876.However,at the beginning,what he actually triedBesides学使to design was not a telephone but a multiple telegraph.During his search to improve the telegraph,Bell invents the first telephone.One of his most famous saying is:"Leave the beaten trackinventedsayingsoccasional and dive into the woods.Every time you do so you will be certain to find somethingoccasionallywhich is completely new in your life."Indeed,what it was his acute curiosity that made his success.thatBell was a honourable inventor all his life.He made his first invention at 11 but his last invention at 75.anand评分标准：有任何错误，包括用词错误、单词拼写错误（含大小写）或语法形式错误，均不给分。第1页（共5页）第二节书面表达（满分25分）一、各档次语言要点配分参考标准档次要点数要点分语言要，点表达情况划档根据第五档521-25语言基本无误，行文连贯，表达清楚第四档16-20语言有少量错误，行文基本连贯，表达基本清楚第三档311~15语言有一些错误，尚能表达第二档26-10语言错误很多，影响表达第一档10-5只能写出与要求内容有关的一些单词

文海火联·2024届韦三起点考考”数学角貌命顺：勇消容史海科什院本状数%150分，专就满对10分要求的1.若复数：一m十3干”不是虚数，侧实数m的值为D.3A.11B.1.-32若集合A二-3k<5.B=4z1-,-6≤o1,则A门6eB5A.{.x|-30时f(x)=1ogx+2x2,则f(一3)三D.-17A.-19B.19C.174.圆C:(x+1)+y=4,直线l:y=x十1被圆C截得的弦长为D.2√②5.已知向量a与b的夹角为60°，且1a=1,1b1=1,设m=a+2b,n=2a-b,则向量m在n方向上A.√2B.2C.4的投影向量为A.DB.nC.√3n36.已知F,F为椭圆C+y(@)的两个焦点，P为椭圆C上一点，若△PEE的周长为4)则椭圆的离心率e=A号B青c号D7.数列{am}中，a1=1,a2=2023,an+2=-a+,则a2024=an1A.2024B.2023C.-2023D.20238△ABC是锐角三角形，角A,B,C所对的边分别为a,b,若2c0sA=b-c,则，千6的取值范围是A.(√2w3)B(,23,2C.(2,十∞)+o0)D.(3二、多项选择题：本题共4小题，每小题5分，共20分，在每小题给出的选项中，有多项符合题目要求.全部选对的得5分，部分选对的得2分，有选错的得0分.9.一种食材的保质时间y(单位：天)与储存温度x(单位：℃)满足函数关系y=2虹+(k、b为常数)若该食品在0℃的保质时间是120天，在20℃的保质时间是30天，则下列描述正确的结论是A.k<0B.该食材储存温度越高保质时间越长C.该食材在10℃的保质时间是60天D.该食材在30℃的保质时间是20天10.下列说法正确的是A.样本数据5,9,10,12,9,7,4,6的25%分位数为9.5B若随机变量6服从两点分布，若P(:=0)=,则D(=日C.若随机变量专服从正态分布N(u,1),且f(x)=P(x一2<

o saw me offment is 1,80.You are expected toshare the rentandh ribill which isreturnabouta month.The Intemet access本文词数：269e of hours,Ieeiswhich isdhefSingapore is set toyou are availabee call me back.Ilnine months!show you around.Byesupertall building.ience abroad第30期A版测试题参考答案as 8 Shenton Way1-5 CABAA6-10 CBBAB11-15 CABABSoutheast Asian city16-20 CCCBB21-25 ADDAB26-30 CDCCAing offices,hotels,aem(自尊心).31-35 BDABD36-40 ADFEB41-45 BADBCThe high-rise buil46-50 ADBCBn in college,51-55 ADCDAby Skidmore,Owinw to me.56-65(One possible version)the firm behind Duba56.its57.an58.has been consideredfor being the world59.who/that60.to keepaddition to the Bur61.as(2.steadiestanother in its63.was passed(4.Legallydesigned other tall65.permissionCTF Finance Centerso I put out写作(One possible version)One World Trade Cdom sawOld第一节Dear Amy,Shenton Way was pLearning that you are in conflict withhe careful oldyour friend,I am writing to offer you somewith local Singaporeathe sidewalk,advice.SOM said its deFirst,I think you should make a sincereove.I slowlyapology to your friend and tell her you havebamboo forests.Dige the nuts.Letbeen aware of your misbehaviour.Second,explain the reason why you failed to keepshow a series of fornthe appointment.Last o east,have aterraces(露天t.Then I wentgood onversation your friend to lether know that you va your friendship.include over 10,00e,but he mustHopefully,myscan be helpfultoelevated green spacoping to watchyou and you can make up with yourfriendto attract birds and borstep.But OldsoonBest wishes!half of the site's lanYours,entered by the publiced in,searchedLiHua第二节“We want to creatHdolding it in hisParagraph 1:ght eyes watchedThinking Icoulde faster to heand jumpedofrWrode Sonnyross the yard to him.It was th

1.(本题满分12分)已知集合A={x2-4x+3>0},B={x2m-3

上单调递增；…4分当01，则需证a112品>)只需证2Int-lnt<1-1-2.1-lt1+1(>)由(1)知，2In1<1-(>,所以只需=n1>训即证lnt2-,>0......10分t+1令8=-作e>,则g0-化之0恒陵立，所以当时，g0在+o)上(t+1)单调递增，所仪g0>g0=0,所n>)成立，一因此，原不等式得证..12分

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3/10B.Avoiding touching things.C.Wearing comfortable clothes.第二部分阅读（共两节，满分50分）第一节（共15小题；每小题2.5分，满分37.5分》阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项。Investment CompetitionAbout the CompetitionThe Wharton Global High School Investment Competition is a free,online investmentsimulation (for high school students(9th to 12th grade)and teachers.Students work inteams of four to seven,guided by a teacher as their advisor ()Together,they learnabout teamwork,communication,risk,companies and industry analysis and many otherimportant aspects of investing.Teams examine a brief case study featuring a potential client and are tasked with workingclosely to meet that client's long-term investment goals.Equipped with an approved stock listand the Wharton Investment Simulator (WInS),which allows them to simulate (stocktrading,students develop an investment strategy,analyze sectors and companies,and build aportfolio(投资组合)using$l00,000 in virtual cash provided by WInS over the course of 10weeks.Winners are selected on the strength of their team strategies,not on the growth oftheir portfolios.ResultsFinal reports are reviewed by a team of judges,who select 50 semi-finalist teams.Thoseteams are invited to present their strategies to a panel of expert judges at the virtual semifi-nals.The top 10 teams from the semifinals move on to the final of the competition,the GlobalFinale,at Wharton in Philadelphia.Please RememberOnce advisors register for the competition,they will receive a confirmation email withinstructions to set up their student team accounts on WInS,our trading platform.Studentteam accounts must be set up no later than September 20,2023.In order to complete theregistration form,advisors will need to:Choose the username and password for their advisor accounts.Provide their school-issued email address,as well as a back-up email address where all com-petition communications will be sent.21.What's the function of WInS?A.Offering virtual cash.B.Studying some brief cases.C.Making people win business.D.Understanding clients'requirements.22.What can we know about the Global Finale?A.All final reports must be delivered to it.【高二英语第3页（共10页）】·23-551B·

又2c=2V5,即c2=a2+b=5,解得a=2,b=1则双曲线的方程为4=1(2)证明：设直线l的方程为y=c+m与双曲线的方程-4y=4联立，可得（4-)+8mx+4m2+4=0直线与双曲线的右支相切，可得△=(8km-4(4-4m+4)小0，可得42=m2+1,设面线与轴交于D,则D会5mo=5 wo+oo又双曲线的渐近线方程为"=±乞1y=2*M72mm·联立y=+m,可得(1-2k'1-2k2m m同理可得（1+2k'1+2k则-4km=2即有△MON面积为定值220.【详解】(1)解：在等腰梯形ADEF中，作EM⊥AD于M,则w=0,F-LaM=3Ew-=5,所以E=V3+9=25连接AC,则AC=42」因为∠AEC=90°，所以EC=25,所以ED2+DC2=EC2,所以CD⊥ED又因为CD⊥AD,且AD∩ED=D,AD,EDC面ADEF,所以CD⊥面ADEF,又由AEc面ADEF,所以CD⊥AE,因为CE⊥AE且CECD-=C,CE,CDc面CDE,所以AE⊥面CDE,又因为AEc面CDE,所以AE⊥DE,因为AE⊥CE,所以LCED就是二面角C-AE-D的面角，os∠CDE=DE=2=V5在直角aCDE中，CE2555所以二面角C-AE-D的余弦值为5.答案第3页，共5页

址某校高二年级在一次研学活动中，从甲地的3处景点、乙地的4处景点中随机远择处开始参观，要求所有景点全部参观且不重复记“第站参观甲地的景点”为事件A。k=1,2,,7,则(e)-月A、4cP4+4)号。号2日如数四mam+pa>0在[等引单调：/停-/5=-八孕则0的可能取值为()96B.C.57三、填空题：本题共4小题，每小题5分，共20分。13.在(x+)的展开式中，x的系数是014.已知抛物线C:y2=4x的焦点为F,准线为l,与x轴行的直线与1和C分别交于4，B两点，若HF-BF,则AB=15.已知点A(2,-1,3),若B(1,0,0),C(1,2,2)两点在直线1上，则点A到直线1的距离为16.已知正四面体ABCD的棱长为2，P为AC的中点，E为AB中点，M是线段DP上的动点，N是面ECD内的动点，则AM+MN的最小值是掉通

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试卷类型：W2023~2024学年度第一学期期中质量调研八年级数学注意事项：1.本试卷共6页，满分120分，时间120分钟，学生直接在试题上答卷：2.答卷前将装订线内的项目填写清楚，题号三总分得分得分评卷人、选择题（共8小题，每小题3分，计24分.每小题只有一个选项是符合题意的）1.若√a-4有意义，则a的值可以是A.-1B.0C.2D.62.下列实数中，属于无理数的是A.1B.2C.ZD.03.下列各组数中，是勾股数的一组是A.1,2,2B.32,42,52C.9,40,41D.6,6,64.在面直角坐标系中，点(4，-3)关于x轴对称的点的坐标是(A.(4,3)B.(4,-3)C.（-4,3)D.(-4,-3)5.下列各式计算正确的是(A.85-25=6B.55+52105C.45x25=86D.45÷25=256.如图，将长为8cm的橡皮筋拉直后放置在水面上，固定两端A和B,然后把中点C垂直向上拉升3cm至点D,则橡皮筋被拉长了A.2 cmB.3 cmC.4 cmD.6 cmB水面7.已知正比例函数y=kx(k≠0)的函数值y随x的增大而增大，则(第6题图)一次函数y=-x+k的图象大致是八年级数学期中质量调研W-1-(共6页)

小石教高三单元测试示范卷全国I@⊙所名校高三单元测试示范卷·数学第十七单元直线与圆(120分钟150分)考情分析服微信扫码2▣考对接点直线与圆是高考常考点元疑难点直线与圆的应用0-、动知识点空间向量及空间中的角、距离观看微课视频型情境题4、7、8、14、20课外题解析下载复课件题序1346101112答案DABBAADBCDACDABC选择题：本题共8小题，每小题5分，共40分.在每小题给出的四个选项中，只有一项是符合题目要求的已知直线：y=kx上有点(cos4,sin4),则直线l的倾斜角a为海M上0着O点A.4B,4-c受-4D.4-π。a1O1=0上家适BEH利【解题分析】，tana=sin 4cos 4=an4=tan(4-),且0<4-<受，直线l的倾斜角&为4-元【京容】【答案D已知圆C的圆心在x轴上，且经过A(5,2),B(一1,4)两点，则圆C的方程为个一床只A.(x+2)2+y2=17B.(x-2)2+y2=13C.(x-1)2+y2=20D.(x+1)2+y2=40【解题分折设圆心坐标为Ca,0),圆C过A(5,2),B(-1,40两点(a-5+(0-2)2=(a+1D+0-4,得a=1,圆半径为r=√/@+1D2+(0-4)2=25,圆C的方程为(x-1)2+y2=20.【答案】Cm=0是“直线4：mx十(2m-1)y+1=0与直线：m十2)一1=0之间的距离为2”的A充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件额分析两行直线同的距高为4干22，即5m4m=0,解得m0或m=青是直线l:r+(2m-1)y十1=0与直线4：mx十(2m一1y1=0之间距离为2”的充分不必要条件【答案】A韦九康算术中的商功箱主要讲述了以立体几何为主的年种形体体积的算，其中“堑塔”是指底面为直角二角形的直按往如图，在驱堵AC一ABC中，M.N分别是A,G,BB的中点，C宽MN的中点.若AG工A店+yAA+:A花，则x+)十A.1A【24:G3DY(新高考)数学-必考-N)】133

18.(本小题满分12分)20.(本在△ABC中，角A,B,C所对的边分别为a,b,c,2 bsinC·ta已()若角B=石求角A的大小：sm2.=数可3(2)若a=2,c0s2A=1598,求65会(1)Sme.(2)21.(19.(本小题满分12分)在已知函数fx)=x(lnx-a),aeR(1)若函数f(x)在[1,6]上单调递增，求a的取值范围；(2)若a>0,求证：f(x)≤x(x-2-lna).XmX-aXmnXtx.nX+|-z大x【高三第三次联考·数学·共6页·第4页】

element nitrogen ()Nitrogen is essential forDsurvival,but often occurs in low concentrationsNowadays,our eyes are often fixed on glowing阅relative to the demand by animals.Likewise,computer,phone and television screens for hugesodium (is limited in many foods in natureportions of the day-whether for work,school orthink of life before supermarkets.So if you need阅读leisure.But after hours of screen time,you maysodium to survive-and all animals do-you aremore likely to adapt a taste for,and seek out,saltynotice pain around your eyes,and over longer解解periods of time your vision may worsen.foods.When we use screens,which are usually very"Nutritional imbalances,even at the elementalclose to our face,the eye's ciliary muscles contractlevel,can limit the growth of animals,"said Lee(睫状肌收缩)，giving the lens(晶状体)a rounderDemi,co-author of the study."We believe animalsshape to focus the image onto the retina(视网膜).should have evolved the ability to taste and enjoyOveruse of the ciliary muscles can lead them tocertain elements and nutrients that are most likelythicken,weakening the eye's ability to relax the lensto be limiting for growth,due to their lowback into a flattened shape.This can elongate (阅concentrations in typical foods."To investigate this assumption,Demi and his阅the eyeball,causing permanent changes to itsstructure and ability to focus light on the retina.colleagues compared the body elementalWhen looking at far-away objects with elongated理composition of three animal groups to the理eyes,a person's point of focus ends up "in front"ofelemental composition of plants,the base of mostfood webs.They predicted that animals who eat解the retina,making the objects appear indistinct andcausing myopia(近视).foods including particular elements that are rareFactors such as a lack of outdoor time can alsoor unpredictable are more likely to have tasteraise the risk of myopia,said Ghorbani Mojarrad,areceptors that reward them for finding those sameregistered optometrist.As rates of myopia haveelements.quickly risen in recent years,particularly in"Because animals have very limited ability tochildren,Mojarrad explained that lifestyle factorschange their elemental composition,the oldare most likely to blame for the increase.Myopia阅saying that "you are what you eat"doesn't reallyapply,"said Demi."Rather,animals are阅can cause permanent blindness because it is a riskfactor for other eye conditions.A 2019 study in therewarded with pleasing tastes for 'eating whatjournal Community Eye Health found that the理解they are',at least from an elemental compositionrisk of developing myopic macular degeneration-viewpoint,which helps reduce the possibility ofa condition that can lead to significant,permanentdietary nutrient limitation."解sight loss-rises as the severity of myopia increases.It also found that people with high myopia are fiveto six times more likely to develop retinaldetachment(视网膜脱落)than people with lowmyopia28.Why do people love a certain taste of food?The World Health Organization recommends noA.It contains little salt.more than one hour daily screen time for children阅B.It has a low concentration in nature.阅under age 5,and none for those under 1 year old.It agrees with what the body needs.D.It prevents the receptors from functioning."Children are now being diagnosed at younger agesthan in the past,"Mojarrad said."If you become理29.What does Lee Demi think affects the growth理myopic at a younger age,by the time you stabilizeof animals?your visual development,you will be a lot moreA.Lack of taste receptorsmyopic than if the onset of myopia was later."An imbalance of nutrients in food.C.Slow evolution of the animals.D.Inability to taste and enjoy certain elements.30.How did Demi and his colleagues do theirresearch?32.What phenomenon is mainly described in the阅A.By doing experiments.first paragraph?By making comparisons阅A.People sit before screens for long hours.C.By analyzing typical cases.Long screen time causes vision problems.D.By referring to previous findings.31.Which of the following would be the best titleC.People enjoy different leisure activities.D.Eve diseases are common in modern society解for the text?解The evolution of good tasteB.Taste:a tool for finding foodC.Receptors:taste detectorsD.The elemental composition of foods6

25.A.推断。根据第二段中的I thought to myself,,"My kids are so little...watch themgrow in life可知，作者担心自己会因为健康问题而过早去世，她害怕自己可能无法陪伴孩子们长大，所以她下定决心开始减肥。26.B。推断。根据第四段中的Running has helped my mind and soul in more waysthan one.which I so enjoy again可知，跑步不仅帮助作者收获了健康的体魄，还帮助她重新找到了生活的目标，现在的作者对生活充满期待。27.D。理解目的。根据最后一段的内容可知，作者是想借自己的故事鼓励体重超标的人走向健康之路。【补充解释】power walking(para.3:(为锻炼而进行的)快走，疾走，暴走C篇主题语境：人与自我一做人与做事本文是说明文。作者带来两个遏制“手机瘾”的妙招，帮助人们关上手机，解锁生活。28.D。理解具体信息。根据第二段中的According to a survey report by ConnectedLife,Singaporean youths spend an average of3.4 hours a day on their phones可知，新加坡的年轻人均每天要花费3.4小时在手机上。29.C。理解具体信息。根据第三段中的One way to stop addiction is to.if you go overyour targeted timing可知，作者建议人们在手机上安装一些监控手机使用时长的应用程序，这样可以在你使用手机的时长超出预设的时间时提醒你。30.D。理解词汇。根据上文中的There is one takeaway from the above two methodsthat effectively和下文中的busy yourself with other activities.out of your mind可知，解决"手机瘾”的方式就是要把自己的时间和精力放在其他有意义的事情上。cuts the

第二节（共5小题；每小题2分，满分10分） 根据短文内容，从短文后的选项中选出能填入空白处的最佳 选项。选项中有两项为多余选项。 The Qingming Festival is celebrated with a three-day nation- al holiday,whose name originates from the saying "Plants start to revive and prosper at Qingming in a clean and bright way. Thus,the festival is called Qingming,which means clean and bright. 36 Tomb sweeping aims to commemorate(纪念)family ancestors while going on a spring outing allows everyone the chance to enjoy the beautiful scenery and the season. Tomb sweeping.37 On this day,the whole family gath- ers in front of their ancestral tombs.They offer fruit and wine to

(Text 8) W:How are you going to raise money for the summer camp? We've only got a few months to go.We're not old enough yet to get a job at the snack bar at the beach.. M:I'm going to make lemonade and sell it to people driving by in front of my house. W:Good idea! M:I did it last summer and made some good money.All I need is a table,lemonade,and some cups.Everyone stops when it's hot outside!What are you going to do for extra money? W:Well,I think I'll set up a car wash near school with my friends.We did it to raise money for our soccer team,and we made a lot of money in a short time.I'm sure I can get them